Month: November 2024

When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\]

s=vt[latex]E=mc^2[/latex][latex] t=t_{1}-t_{2}[/latex][latex] t=\frac{s}{v}[/latex]

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